Ejercicio Exercise 2 · Física I URV 2024

Tema: Oscil·lacions: harmòniques, esmorteïdes i forçades · Del examen Physics I - 1st & 2nd Partial Exam (January 2024) (2024)

Enunciado

Exercise 2 (10 points). Damped and forced harmonic oscillations

A mass of m=6 kgm = 6\text{ kg} hangs from the bottom of a vertical spring having a constant k=150 N/mk = 150\text{ N/m}. The mass experiences a viscous damping force directly proportional to its instantaneous velocity. At time t=0t = 0, the mass is located at x(0)=1 cmx(0) = 1\text{ cm} with an initial velocity of v(0)=1 m/sv(0) = 1\text{ m/s}. Calculate:

a)

The damping constant bb and the period of the damped oscillation, knowing that the damping force has a magnitude of 80 N80\text{ N} at a speed of 2 m/s2\text{ m/s}. [2 points]

b)

The equation describing the instantaneous position x(t)x(t) of the mass fulfilling the initial conditions. [2 points]

c)

A qualitative graphical representation showing the amplitude variation over time, A(t)A(t). [2 points]

d)

The angular frequency (ω\omega) of an external periodic force with a static displacement equivalent amplitude of 2 cm2\text{ cm} that produces amplitude resonance. Find the resulting amplitude and phase of the oscillations at this condition. [2 points]

e)

If the external driving force is given by F(t)=5cos⁡(5t) NF(t) = 5\cos(5t)\text{ N}, explain whether any type of resonance will be induced. Compute the steady-state amplitude and phase under these specific conditions. [2 points]

Enunciado: Ejercicio Exercise 2 · Física I URV 2024

Solución

Según los criterios oficiales de corrección

a) The damping constant b

Solución: 4040 N·s/m / 4040 kg/s

a) The period of the damped oscillation

Solución: 1,6861{,}686 s

b) The equation describing the instantaneous position x(t) of the mass fulfilling the initial conditions

Solución: e−103t[0,01cos⁡(3,727t)+0,2773sin⁡(3,727t)]e^{-\frac{10}{3}t} [0{,}01\cos(3{,}727t) + 0{,}2773\sin(3{,}727t)] m / 0,2775e−3,333tcos⁡(3,727t−1,535)0{,}2775 e^{-3{,}333t}\cos(3{,}727t - 1{,}535) m

c) A qualitative graphical representation showing the amplitude variation over time, A(t)

Solución: The envelope curve representing the oscillation amplitude decreases exponentially over time according to A(t)=A0e−γt=0.2775e−3.333t mA(t) = A_0 e^{-\gamma t} = 0.2775 e^{-3.333t}\text{ m}. The curve starts at A(0)≈0.278 mA(0) \approx 0.278\text{ m} on the vertical axis and decays asymptotically toward zero as t→∞t \to \infty, with characteristic decay time τ=1/γ=0.3 s\tau = 1/\gamma = 0.3\text{ s}.

d) The angular frequency (ω) that produces amplitude resonance

Solución: 1,6671{,}667 rad/s / 53\frac{5}{3} rad/s

d) Resulting amplitude at amplitude resonance

Solución: 0,02010{,}0201 m / 2,012{,}01 cm

d) Phase of the oscillations at amplitude resonance

Solución: 0,4640{,}464 rad / 26,57∘26{,}57^\circ

e) Explain whether any type of resonance will be induced

Solución: Velocity resonance (phase resonance or frequency of maximum power absorption), because ω=ω0=5 rad/s\omega = \omega_0 = 5\text{ rad/s}.

e) Steady-state amplitude under these conditions

Solución: 0,0250{,}025 m / 2,52{,}5 cm

e) Steady-state phase under these conditions

Solución: π/2\pi/2 rad / 1,5711{,}571 rad / 90∘90^\circ

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