Ejercicio Exercise 2 · Física I URV 2024

Tema: Oscil·lacions: harmòniques, esmorteïdes i forçades · Del examen Examen Primer Parcial (19/01/2024) (2024)

Enunciado

Exercise 2 (10 points). Damped and driven oscillations

A mass of m=6 kgm = 6\text{ kg} hangs vertically from a spring of stiffness constant k=150 N/mk = 150\text{ N/m}. The damping force is linear with the instantaneous velocity of the body. At t=0t = 0, the mass is observed at a displacement x(0)=1 cm=0.01 mx(0) = 1\text{ cm} = 0.01\text{ m} with a downward/positive velocity v(0)=1 m/sv(0) = 1\text{ m/s}. Answer the following:

a.

Find the damping parameter bb (or β\beta) and the natural damped period TT, knowing that the resistive force equals 80 N80\text{ N} when the speed reaches 2 m/s2\text{ m/s}. [2 points]

b.

Write the explicit expression for the position as a function of time, x(t)x(t), incorporating the stated initial values. [2 points]

c.

Plot the damping envelope representing the time-dependent amplitude A(t)A(t). [2 points]

d.

Determine the driving angular frequency ωext\omega_{\text{ext}} required to obtain amplitude resonance if an external driving force of amplitude F0=0.02 NF_0 = 0.02\text{ N} is applied. Calculate the steady-state amplitude and the phase shift under these conditions. [2 points]

e.

If the external force is modified to F(t)=5cos⁡(5t) NF(t) = 5\cos(5t)\text{ N}, state whether resonance takes place and identify its type. Compute the resulting amplitude and phase. [2 points]

Enunciado: Ejercicio Exercise 2 · Física I URV 2024

Solución

Según los criterios oficiales de corrección

a. Find the damping parameter b (or β)

Solución: 4040 N·s/m / 4040 kg/s

a. Natural damped period T

Solución: 1.681.68 s

b. Write the explicit expression for the position as a function of time, x(t)

Solución: 0.28e−3.33tcos⁡(3.73t−1.53)0.28 e^{-3.33t} \cos(3.73t - 1.53) m

c. Plot the damping envelope representing the time-dependent amplitude A(t)

Solución: The envelope curve corresponds to A(t)=A0e−γt=0.28e−3.33tA(t) = A_0 e^{-\gamma t} = 0.28 e^{-3.33t}, starting at (0,0.28 m)(0, 0.28\text{ m}) and exponentially decaying towards zero.

d. Driving angular frequency required to obtain amplitude resonance

Solución: 1.681.68 rad/s / 1.681.68 s⁻¹

d. Steady-state amplitude at amplitude resonance

Solución: 1.34⋅10−41.34\cdot 10^{-4} m / 0.1340.134 mm / 0.01340.0134 cm

d. Phase shift under amplitude resonance conditions

Solución: −0.47-0.47 rad

e. State whether resonance takes place and identify its type for F(t) = 5 cos(5t) N

Solución: velocity resonance

e. Resulting amplitude for F(t) = 5 cos(5t) N

Solución: 0.0250.025 m / 2.52.5 cm / 2525 mm

e. Resulting phase for F(t) = 5 cos(5t) N

Solución: −π/2-\pi/2 rad / −1.57-1.57 rad

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