Ejercicio Exercise 2 · Física I URV 2024
Tema: Oscil·lacions: harmòniques, esmorteïdes i forçades · Del examen Examen Primer Parcial (19/01/2024) (2024)
Enunciado
Exercise 2 (10 points). Damped and driven oscillations
A mass of hangs vertically from a spring of stiffness constant . The damping force is linear with the instantaneous velocity of the body. At , the mass is observed at a displacement with a downward/positive velocity . Answer the following:
a.
Find the damping parameter (or ) and the natural damped period , knowing that the resistive force equals when the speed reaches . [2 points]
b.
Write the explicit expression for the position as a function of time, , incorporating the stated initial values. [2 points]
c.
Plot the damping envelope representing the time-dependent amplitude . [2 points]
d.
Determine the driving angular frequency required to obtain amplitude resonance if an external driving force of amplitude is applied. Calculate the steady-state amplitude and the phase shift under these conditions. [2 points]
e.
If the external force is modified to , state whether resonance takes place and identify its type. Compute the resulting amplitude and phase. [2 points]

Solución
Según los criterios oficiales de corrección
a. Find the damping parameter b (or β)
Solución: N·s/m / kg/s
a. Natural damped period T
Solución: s
b. Write the explicit expression for the position as a function of time, x(t)
Solución: m
c. Plot the damping envelope representing the time-dependent amplitude A(t)
Solución: The envelope curve corresponds to , starting at and exponentially decaying towards zero.
d. Driving angular frequency required to obtain amplitude resonance
Solución: rad/s / s⁻¹
d. Steady-state amplitude at amplitude resonance
Solución: m / mm / cm
d. Phase shift under amplitude resonance conditions
Solución: rad
e. State whether resonance takes place and identify its type for F(t) = 5 cos(5t) N
Solución: velocity resonance
e. Resulting amplitude for F(t) = 5 cos(5t) N
Solución: m / cm / mm
e. Resulting phase for F(t) = 5 cos(5t) N
Solución: rad / rad
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